# Program to count the number of each vowels
# string of vowels
vowels = 'aeiou'
ip_str = 'Hello, have you tried our tutorial section yet?'
# make it suitable for caseless comparisions
ip_str = ip_str.casefold()
# make a dictionary with each vowel a key and value 0
count = {}.fromkeys(vowels,0)
# count the vowels
for char in ip_str:
if char in count:
count[char] += 1
print(count)
Source Code: Using a list and a dictionary comprehension
# Using dictionary and list comprehension
ip_str = 'Hello, have you tried our tutorial section yet?'
# make it suitable for caseless comparisions
ip_str = ip_str.casefold()
# count the vowels
count = {x:sum([1 for char in ip_str if char == x]) for x in 'aeiou'}
print(count)
Output
{'o': 5, 'i': 3, 'a': 2, 'e': 5, 'u': 3}
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